Question

dx/√4x+5 найти интеграл

Answer 1

$LARGE \ int{mathrm{dx}oversqrt{4x+5}}=begin{vmatrix} 4x+5=t^2\ mathrm{dx}={tmathrm{dt}over2} end{vmatrix}={1over2}int{tmathrm{dt}oversqrt{t^2}}={1over2}t+C={1over2}sqrt{4x+5}+C$