Question

a) x^2+4>4(4x-15)
б) (4x+3)(3x-2)>(12x-11)(x+1)

Answer 1

А) x^2+4>16x-60
x^2+4-16x+60>0
f(x)=0
f(x)=x^2-16x+64
x^2-16x+64=0
D=256-256=0 => 1 корень
x=-b2a
x=162*1
x=8