Question

решите уравнение (х^2+y^2+y)^2=х^2+y^2,при у =0

Answer 1

(x^2 + 0^2 + 0)^2 = x^2 + 0^2
(x^2)^2 = x^2
(x^2)^2 - x^2 = 0
(x^2 - x)(x^2 + x) = 0
x(x - 1)*x*(x + 1) = 0
x^2 *(x - 1)(x + 1) = 0

1) x^2 =0 ==> x1 = 0
2) x - 1 = 0 ==> x2 = 1;
3) x + 1 = 0 ==> x3 = - 1 

ОТВЕТ
- 1; 0 ; 1 

Answer 2

Спасибо,выручил.

Answer 3

аха н,з,ч!