Question

25x^4-50x^3+14x^2+10x+1=0

Answer 1

25x^4-50x^3+14x^2+10x+1=0
25x^4-50x^3+14x^2+10x+1=(х-1)*(5х+1)*(5х^2-6х-1)
х-1=0
х=0
5х+1=0
5х=-1
5х^2-6х-1=0
D=(-6)^2-(-4*(5*1))=56
х=-1/5
х=- корень из (14)-3/5
х=1
х=корень из (14)+3/5