Question

x²-3xy+3y-x=2, розвяжите в целых числах, умоляю помогите!

Answer 1

x^2 - x - 3xy + 3y = 2
x (x - 1) - 3y(x - 1) = 2
(x - 1)*(x - 3y) = 2 

y = 0;  ± 1; ± 2

Если y = 0
(x - 1)*x = 2
x^2 - x - 2 = 0
D = 1 + 4*2 = 9
x1 = ( 1 + 3)/2 = 4/2 = 2
x2 = (1 - 3)/2 = - 2/2 = - 1

ОТВЕТ
( - 1; 0) ; (2; 0)