Question

{-2х1+х2-х3=8 -3Х1-Х2+2Х3=11 -2Х1+Х2+2Х3=-3 МЕТОД КРАМЕРА ПОМОГИТЕ ПОЖАЛУЙСТА

Answer 1

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c4fa856d128ffb657e4ee66f2b384ff5.pdf

Answer 2

$begin{cases}-2x_1+x_2-x_3=8\-3x_1-x_2+2x_3=11\-2x_1+x_2+2x_3=-3end{cases}\mathcal4= left[begin{array}{ccc}-2&1&-1\-3&-1&2\-2&1&2end{array}right]=4-4+3+2+4+6=15\mathcal4_{x_1}= left[begin{array}{ccc}8&1&-1\11&-1&2\-3&1&2end{array}right]=-16-6-11+3-22-16=-68\mathcal4_{x_2}=left[begin{array}{ccc}-2&8&-1\-3&11&2\-2&-3&2end{array}right]=-44-32-9-22+48-12=-71\mathcal4_{x_3}=left[begin{array}{ccc}-2&1&8\-3&-1&11\-2&1&-3end{array}right]=-6-22-24-16-9+22=-55$

$x_1=frac{mathcal4{x_1}}{mathcal4}=-frac{68}{15} ;x_2=frac{mathcal4{x_2}}{mathcal4}=-frac{71}{15} ;x_3=frac{mathcal4{x_3}}{mathcal4}=-frac{55}{15}=-frac{11}{3}$

Проверка:
$begin{cases}frac{2*68}{15}-frac{71}{15}+frac{55}{15}=8\frac{3*68}{15}+frac{71}{15}-frac{2*55}{15}=11\frac{2*68}{15}-frac{71}{15}-frac{2*55}{15}=-3end{cases}= textgreater begin{cases}8=8\11=11\-3=-3end{cases}$

c4fa856d128ffb657e4ee66f2b384ff5.pdf