Question

1) log5(3x+1)>2
2) log1/7(4x+1)<-2
помогите плиз

Answer 1

log5(3x+1)>2
{3x+1>0
{log5(3x+1)>log5^5^2
{3x>-1
{log5(3x+1)>log5^25(5>1)