Question

a)
12y^3
_____
-42y^5
в)
5а^2. 5a
_____ = ____
6a. 6

Answer 1

$frac{12y {}^{3} }{ - 42y {}^{5} } = frac{4}{ - 15y {}^{2} } = - frac{4}{15y {}^{2} } \ \ frac{5a {}^{2} }{6a} = frac{5a}{6}: : : : : : : frac{5a}{6} = frac{5a}{6}$