Question

Решите уравнение!!!
Cos2x+3sinx=2

Answer 1

cos2x=1-2sin²x
1-2sin²x+3sinx=2
2sin²x-3sinx+1=0
2t²-3t+1=0
t1=1/2
t2=1
sinx=1/2
x=π/6+2πk
x=5π/6+2πk
sinx=1
x=π/2+2πk