Ответы
Ответ дал:
0
Думаю, что так :
![frac{2a + 3 }{6 - 2a} = frac{2a+3}{- 2(a - 3)} = frac{(2a+3) * (-1)(a+3)}{-2(a-3) * (-1)(a+3)} = frac{- (2a+3)(a+3)}{2(a-3)(a+3)} = frac{(-2a-3)(a+3)}{2(a^2-3^2)} = \ \ = frac{-2a^2-6a-3a-9}{2(a^2 - 9)} = frac{-2a^2-9a-9}{2(a^2 - 9)} = frac{-(2a^2+9a+9)}{2(a^2-9)} = - frac{2a^2+9a+9}{2(a^2-9)} \ \](https://tex.z-dn.net/?f=frac%7B2a+%2B+3+%7D%7B6+-+2a%7D+%3D+frac%7B2a%2B3%7D%7B-+2%28a+-+3%29%7D+%3D+frac%7B%282a%2B3%29+%2A+%28-1%29%28a%2B3%29%7D%7B-2%28a-3%29+%2A+%28-1%29%28a%2B3%29%7D+%3D+frac%7B-+%282a%2B3%29%28a%2B3%29%7D%7B2%28a-3%29%28a%2B3%29%7D+%3D+frac%7B%28-2a-3%29%28a%2B3%29%7D%7B2%28a%5E2-3%5E2%29%7D+%3D+%5C+%5C+%3D+frac%7B-2a%5E2-6a-3a-9%7D%7B2%28a%5E2+-+9%29%7D+%3D+frac%7B-2a%5E2-9a-9%7D%7B2%28a%5E2+-+9%29%7D+%3D++frac%7B-%282a%5E2%2B9a%2B9%29%7D%7B2%28a%5E2-9%29%7D+%3D+-+frac%7B2a%5E2%2B9a%2B9%7D%7B2%28a%5E2-9%29%7D+%5C++%5C+ "frac{2a + 3 }{6 - 2a} = frac{2a+3}{- 2(a - 3)} = frac{(2a+3) * (-1)(a+3)}{-2(a-3) * (-1)(a+3)} = frac{- (2a+3)(a+3)}{2(a-3)(a+3)} = frac{(-2a-3)(a+3)}{2(a^2-3^2)} = \ \ = frac{-2a^2-6a-3a-9}{2(a^2 - 9)} = frac{-2a^2-9a-9}{2(a^2 - 9)} = frac{-(2a^2+9a+9)}{2(a^2-9)} = - frac{2a^2+9a+9}{2(a^2-9)} \ \")
Вас заинтересует
3 года назад
3 года назад
3 года назад
9 лет назад