Ответы
Ответ дал:
0
1)![2^{5x+3} textless 2^{-2(2x+1)/x} \ \ 2 textgreater 1 \ \ 5x+3 textless frac{-4x-2}{x} \ \ frac{5x^2+7x+2}{x} textless 0 \ \ D=9 \ \ x_{1} =-1 \ \ x_{2} =-2/5 \ \](https://tex.z-dn.net/?f=+2%5E%7B5x%2B3%7D++textless+++2%5E%7B-2%282x%2B1%29%2Fx%7D++%5C++%5C+2+textgreater++1+%5C++%5C+5x%2B3+textless+++frac%7B-4x-2%7D%7Bx%7D++%5C++%5C++frac%7B5x%5E2%2B7x%2B2%7D%7Bx%7D++textless++0+%5C++%5C+D%3D9+%5C++%5C++x_%7B1%7D+%3D-1+%5C++%5C++x_%7B2%7D+%3D-2%2F5+%5C++%5C+ "2^{5x+3} textless 2^{-2(2x+1)/x} \ \ 2 textgreater 1 \ \ 5x+3 textless frac{-4x-2}{x} \ \ frac{5x^2+7x+2}{x} textless 0 \ \ D=9 \ \ x_{1} =-1 \ \ x_{2} =-2/5 \ \")
-----(-1)++++(-2/5)------(0)+++++++
x∈(-∞;-1)U(-2/5;0)
2)
![3^{2x-3} textgreater 3^{ frac{2(6-4x)}{x+1} } \ \ 3 textgreater 1 \ \ 2x-3 textgreater frac{12-8x}{x+1} \ \ frac{2x^2-3x+2x-3-12+8x}{x+1} textgreater 0 \ \ frac{2x^2+7x-15}{x+1} textgreater 0 \ \ D=169 \ \ x_{1} =-5 \ \ x_{2} =1.5 \ \](https://tex.z-dn.net/?f=+3%5E%7B2x-3%7D++textgreater+++3%5E%7B+frac%7B2%286-4x%29%7D%7Bx%2B1%7D+%7D++%5C++%5C+3+textgreater++1+%5C++%5C+2x-3+textgreater+++frac%7B12-8x%7D%7Bx%2B1%7D++%5C++%5C+frac%7B2x%5E2-3x%2B2x-3-12%2B8x%7D%7Bx%2B1%7D++textgreater++0+%5C++%5C++frac%7B2x%5E2%2B7x-15%7D%7Bx%2B1%7D++textgreater++0+%5C++%5C+D%3D169+%5C++%5C++x_%7B1%7D+%3D-5+%5C++%5C++x_%7B2%7D+%3D1.5+%5C++%5C+ "3^{2x-3} textgreater 3^{ frac{2(6-4x)}{x+1} } \ \ 3 textgreater 1 \ \ 2x-3 textgreater frac{12-8x}{x+1} \ \ frac{2x^2-3x+2x-3-12+8x}{x+1} textgreater 0 \ \ frac{2x^2+7x-15}{x+1} textgreater 0 \ \ D=169 \ \ x_{1} =-5 \ \ x_{2} =1.5 \ \")
-----(-5)+++++(-1)------(1.5)+++++
x∈(-5;-1)U(1.5;+∞)
-----(-1)++++(-2/5)------(0)+++++++
x∈(-∞;-1)U(-2/5;0)
2)
-----(-5)+++++(-1)------(1.5)+++++
x∈(-5;-1)U(1.5;+∞)
Ответ дал:
0
Большое спасибо
Вас заинтересует
2 года назад
3 года назад
3 года назад
9 лет назад
9 лет назад
10 лет назад
10 лет назад