Question

помогите срочно!!!!!!!!

Answer 1

( x^4)'=(x^3*x)'=x^3' * x+x^3 * x'=3x^( x^4)'=(x^3*x)'=x^3' * x+x^3 * x'=3x^2 * x+x^3 * 1=3x^3+x^3=4x^32 * x+x^3 * 1=3x^3+x^3=4x^3