Question

Найдите решение системы:
4(3х - 4у) + 14 = 3(5х + 2у)
-2(х - 6у) = 5(3х - 4у) - 1

Answer 1

$left { {{4(3x - 4y) + 14 = 3(5x + 2y)} atop {-2(x - 6y) = 5(3x - 4y) - 1}} right. \ left { {{12x-16y+14=15x+6y} atop {-2x+12y=15x-20y-1}} right. \ left { {{15x+6y+16y-12x=14} atop {15x+2x-20y-12y=1}} right. \ left { {{3x+22y=14} atop {17x-32y=1}} right. \3x=14-22y \x= frac{14-22y}{3} \17*frac{14-22y}{3} -32y=1 \17(14-22y)-96y=3 \238-374y-96y=3 \-470y=-235 \y= frac{235}{470} = frac{1}{2}=0,5 \x= frac{14-22*0,5}{3} = frac{14-11}{3} =1$
Ответ: (1;0,5)

Answer 2

Спасибо)