Question

Разложите квадратный хрехчлен
6x²+5x-4

Answer 1

$6x^2+5x-4 \ D=25+6*4*4=121 \ x_{1} =-5+11/12=6/12=1/2 \ x_{2} =-5-11/12=-16/12=-8/6=-4/3 \ 6(x-1/2)(x+4/3)$
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$6x^2+5x-4 \ 6x^2+8x-3x-4 \ 2x(3x+4)-1(3x+4) \ (3x+4)(2x-1)$