Question

Решите уровнение (6x-1)^2-(3x-5)^2=0

Answer 1

$(6x-1)^2-(3x-5)^2=0\36x^2-12x+1-9x^2+30x-25=0\27x^2+18x-24=0\9x^2+6x-8=0\D=36+288=324\x_1=frac{-6-18}{18} =-frac{4}{3} \x_2=frac{2}{3}$

Answer 2

(6x-1-3x+5)(6x-1+3x-5)=0
(3x+4)(9x-6)=0
3x+4=0
x=-4/3
x=-1 1/3

9x-6=0
x=6/9
x=2/3