Question

tg x > sqrt 3

25 баллов.

Answer 1

$tgx textgreater sqrt3; ; Rightarrow ; ; frac{pi }{3}+pi n textless x textless frac{pi }{2}+pi n; ,; nin Z$

Answer 2

tgx>√3
x=arctg√3
π/3+πk<x<π/2+πk;k€Z