Question

Решите плиз : x^2-19x+60=0

Answer 1

$x^2-19x+60=0\ x^2-4x-15x+60=0\ x(x-4)-14(x-4)=0\ (x-4)(x-15)=0\ x-4=0--- textgreater x=4\ x-15--- textgreater x=15\ Otvet: x1=4;; ; ;;x2=15$