Question

Решите:
y^6-9=
100x^4-9y^10=
0,01m^2-25n^8=

Answer 1

$y^6-9=(y^3-3)(y^3+3)$
$100x^4-9y^{10}=(10x^2 - 3y^5)(10x^2 + 3y^5)$
$0,01m^2-25n^8=(0,1m-5n^4)(0,1m+5n^4)$