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Ответ дал:
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По закону сохранения энергии:
![boxed{W_K_{1} + W_Pi_{1} = W_K_{2} + W_Pi_{2}} ; W_Pi = mgh ; W_K = dfrac{mupsilon^{2}}{2} \ \ W_Pi = W_K ; mgh = dfrac{mupsilon^{2}}{2} ; rightarrow 2gh = upsilon^{2} rightarrow h = dfrac{upsilon^{2}}{2g} \ \ h = dfrac{20^{2}}{2*10} = 20 [M] boxed{W_K_{1} + W_Pi_{1} = W_K_{2} + W_Pi_{2}} ; W_Pi = mgh ; W_K = dfrac{mupsilon^{2}}{2} \ \ W_Pi = W_K ; mgh = dfrac{mupsilon^{2}}{2} ; rightarrow 2gh = upsilon^{2} rightarrow h = dfrac{upsilon^{2}}{2g} \ \ h = dfrac{20^{2}}{2*10} = 20 [M]](https://tex.z-dn.net/?f=boxed%7BW_K_%7B1%7D+%2B+W_Pi_%7B1%7D+%3D+W_K_%7B2%7D+%2B+W_Pi_%7B2%7D%7D++%3B++W_Pi+%3D+mgh++%3B++W_K+%3D++dfrac%7Bmupsilon%5E%7B2%7D%7D%7B2%7D+%5C+%5C+W_Pi+%3D+W_K++%3B++mgh+%3D++dfrac%7Bmupsilon%5E%7B2%7D%7D%7B2%7D++%3B++rightarrow++2gh+%3D+upsilon%5E%7B2%7D++rightarrow++h+%3D++dfrac%7Bupsilon%5E%7B2%7D%7D%7B2g%7D++%5C+%5C+h+%3D++dfrac%7B20%5E%7B2%7D%7D%7B2%2A10%7D+%3D+20++%5BM%5D)
Ответ: h = 20 м
Ответ: h = 20 м
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