Question

2а-1/2a-2a/2a-1-1/2a-4a^2

Answer 1

$frac{2a-1}{2a}- frac{2a}{2a-1}- frac{1}{2a-4a ^{2} }= frac{2a-1}{2a}- frac{2a}{2a-1}- frac{1}{2a(1-2a)} = frac{2a-1}{2a}- frac{2a}{2a-1} +$$+ frac{1}{2a(2a-1)} = frac{(2a-1)(2a-1)-2a*2a+1}{2a(2a-1)}= frac{4 a^{2}-4a+1-4 a^{2} +1 }{2a(2a-1)} = frac{2-4a}{2a(2a-1)} =$$= frac{2(1-2a)}{2a(2a-1)} =- frac{1}{a}$