Question

a²-9/2a² * a/2a+b при a=1/27
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Answer 1

$frac{ a^{2} -9}{2a^{2} } * frac{a}{2a+b} = frac{(a-3)(a+3)}{2a(2a+b)}$

при  а=1/27

$frac{( frac{1}{27} -3)( frac{1}{27} +3)}{2* frac{1}{27} (2* frac{1}{27} +b)}=- frac{2 frac{26}{27}*3 frac{1}{27} }{ frac{2}{27}( frac{2}{27} +b) } =- frac{80*82}{27*27} :( frac{4}{27*27} + frac{2b}{27} )= \ \ - frac{80*82}{27*27} : frac{4+54b}{27*27} =-frac{80*82}{27*27}* frac{27*27}{2(2+17b)} =- frac{3280}{2+17b}$