Question

2х/х+2+1/х-2= 4/х^2-4помогите пожалуйста

Answer 1

$frac{2x}{x+2} + frac{1}{x-2} = frac{4}{x^2-4} \ 2x(x-2)+1(x+2)=4 \ 2x^2-4x+x+2 - 4 = 0 \ 2x^2 -3x-2 = 0 \ boxed{D=b^2-4ac} \ D = (-3)^2 - 4 cdot 2 cdot (-2) = 9 + 16 = 25 \ boxed{x_1 ; x_2 = frac{-b pm sqrt{D} }{2a}} \ \ x_1 ; x_2 = frac{3 pm 25 }{4} = x_1 = 7 ; x_2 = -5,5$