Question

Вычислить
1)tg45°+ctg²30°cos45°
2)sin60°+sin²45°

Answer 1

$tg45 ^{o} + Ctg ^{2}30 ^{o}Cos ^{2} 45 ^{o}=1+( sqrt{3} ) ^{2}* (frac{ 1 }{ sqrt{2} }) ^{2} =1+3* frac{1}{2}=1+1,5=2,5\\Sin60 ^{o}+Sin ^{2}45 ^{o} = frac{1}{2}+( frac{1}{ sqrt{2} }) ^{2}= frac{1}{2} + frac{1}{2} =1$