Question

Помогите решить уравнение с параметром

Answer 1

${a}^{2} x - a = x + 1 \ {a}^{2} x - a - x - 1 = 0 \ x( {a}^{2} - 1) - (a + 1) = 0 \ x(a - 1)(a + 1) - (a + 1) = 0 \ (a + 1)(ax - x - 1) = 0 \ a = - 1 \ ax - x - 1 = 0 \ x(a - 1) = 1 \ x = frac{1}{a - 1}$
х=-0,5