Question

x^2+0,5x-13/x^2-0,5x-14<=1 прошууу

Answer 1

(x²-0,5x-13)/(x²-0,5x-14)≤1
(x²-0,5x-13)/(x²-0,5x-14)-1≤0
(x²-0,5x-13-x²+0,5x+14)/(x²-0,5x-14)≤0
1/(x²-0,5x-14)≤0
ОДЗ: x²-0,5x-14≠0  |×2   2x²-x-28≠0   D=225   x₁≠4    x₂≠-3,5  
 1/((x-4)*(x+3,5))≤0
-∞____+_____-3,5____-_____4____+_____+∞ 
Ответ: x∈(-3,5;4).