Question

2tg^2 60градусов - cth^2 30градусов - sin30cos30

Answer 1

${ cot }^{2} (30) = { tan }^{2} (60) \ 2 { tan }^{2} (60) - { tan}^{2} (60) - sin(30) cos(30) = { tan }^{2} (60) - sin(30) cos(30) = { sqrt{3} }^{2} - frac{1}{2} sin(60) = 3 - frac{1}{2} times frac{ sqrt{3} }{2} = 3 - frac{ sqrt{3} }{4} = frac{12 - sqrt{3} }{4}$