Question

Решите систему уравнений {8(2x+y)-2y=-76,
4(x-3y)+10y=-12.

Answer 1

$16 x + 8y - 2y = - 76 \ 4x - 12y + 10y = - 12 \ 16x + 6y = - 76 \ 4x - 2y = - 12 |3 \ 16x + 6y = - 76 \ 12x - 6y = - 36 \ 28x = - 112 \ x = - 4 \ y = - 2$