Question

Решите неравенства:
4ˣ ≥ 3ˣ

Answer 1

$4^xgeq 3^x bigg| :3^x>0\ bigg(frac{4}{3}bigg)^xgeq 1\ y=bigg(frac{4}{3}bigg)^x ; ; vozrastaet, t.k. ; frac{4}{3} >1 => \ znak ;; ne;; menyaetsya=>\ bigg(frac{4}{3}bigg)^xgeq frac{4}{3}^0\ xgeq0\ x in [0; +infty)$