Question

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Answer 1

(sin(x) + cos(x))² = 1 + cos(x)
sin²x + 2sinxcosx + cos²x - 1 - cosx = 0
(sin²x + cos²x = 1)
1 + 2sinxcosx - 1 - cosx = 0
2sinxcosx - cosx = 0
cosx(2sinx - 1) = 0
cosx = 0;   
x = π/2
2sin x = 1
sinx = 1/2
x = π/6
Ответ: 30°