Question

Решить неравенства методом интервалов
(5x-10)(6x-12)^14*(x+5)>0

Answer 1

$(5x-10)(6x-12)^1^4cdot(x+5) textgreater 0 \ (5x-10)(6x-12) cdot (x+5) textgreater 0 \ x_1 = 2 ; x_2 = 2 ; x_3 = -5 \ x in (-infty;-5) cup (2;infty)$