Question

Система : 16-x²≥0
x-2>0

Answer 1

$left { {{16-x^2 geq 0} atop {x-2 geq 0}} right. \\ left { {{x^2-4^2 leq 0} atop {x geq 2}} right. \\ left { {{(x+4)(x-4) leq 0} atop {x geq 2}} right. \\ left { {{x-4 leq 0} atop {x geq 2}} right. \\ left { {{x leq 4} atop {x geq 2}} right. \\ 2 leq x leq 4\\ xin[2; 4]$