Question

1.Решить систему
4x+y=10
2x-3y=12

Answer 1

у=10-4х
2х-30+12х=12
14х=42
х=3
у=10-4*3=10-12=-2
ответ:х=3, у=-2

Answer 2

$left { {{4x+y=10} atop {2x-3y=12}} right. \ left { {{12x+3y=30} atop {2x-3y=12}} right. \ 12x+3y+2x-3y=30+12 \ 14x=42 \ x = 3 \ \ 4x+y=10 \ 12+y=10 \ y=10-12 \ y=-2$