Question

25x^2-36>0
решите неравенства

Answer 1

$25x^2-36 textgreater 0 \ (5x-6)(5x+6) textgreater 0 \ x_1 =-1 frac{1}{5} ; x_2 = 1 frac{1}{5} \ x in (-infty;-1 frac{1}{5}) cup ( 1frac{1}{5};+infty)$