Question

sin2x + sin^2x + cos^2x = 1/2

Answer 1

$sin2x + sin^2x + cos^2x = frac{1}{2} \sin2x+(sin^2x+cos^2x)= frac{1}{2} \sin2x+1= frac{1}{2} \sin2x= frac{1}{2} -1 \sin2x=- frac{1}{2} \2x=- frac{pi}{6} +2pi n \x_1=- frac{pi}{12} +pi n, n in Z \2x=- frac{5pi}{6} +2pi n \x_2=- frac{5pi}{12} +pi n, n in Z$
Ответ: $x_1=- frac{pi}{12} +pi n, n in Z ; x_2=- frac{5pi}{12} +pi n, n in Z$