Question

найти производную сложной функции y=tg^3(x)/(9(m^2+n^2))

Answer 1

y = tg³(x) / (9(m^2 + n^2))
m, n - const
y' = tg²(x)/(3(m^2 + n^2)cos²(x))

Answer 2

$y=frac{tg^3x}{9(m^2+n^2)}\\y'= frac{1}{9(m^2+n^2)}cdot 3tg^2xcdot frac{1}{cos^2x}=frac{tg^2x}{3(m^2+n^2)cdot cos^2x}$