Question

2x²+5x-12>0 решите неравенство

Answer 1

$2x^2+5x-12 textgreater 0 \ (x+4)(x- 1,5) textgreater 0 \ x in (-infty;-4)cup( 1,5 ; +infty)$

Answer 2

D=25-4*2*(-12)=25+96=121

x1=(-5+11)/2*2=6/4=1,5

x2=(-5-11)/2*2=-16/4=-4

Ответ: (-∞;-4)∪(1,5;+∞)