Question

sin2x/cosx-sin(pi+2)

Answer 1

$frac{sin(2x)}{cos(x)} -sin(pi+2)=frac{2sin(x)cos(x)}{cos(x)} -(sin(pi)cos(2)+cos(pi)sin(2))=\=2sin(x)-(-sin(2))=2sin(x)+sin(2)$