Question

Разложите на множители 49-(5d+3)^2
СРОЧНО!

Answer 1

49-(5d+3)^2=7²-(5d+3)²=(7+5d+3)(7-5d-3)=(10+5d)(4-5d)=5(2+d)(4-5d)

Answer 2

49-(5d+3)²=7-(5d+3))*(7+(5d+3))=(7-5d)*(10+5d)=(4-5d)*5(2+d)=5(4-5d)*(2+d)