Question

Решите неравенство, пожалуйста

Answer 1

$frac{lgx}{x^2-3x+2} textless 0; ,; ; ; ODZ:; x textgreater 0; ,xne 1; ,; xne 2\\a); ; left { {{lgx textgreater 0} atop {x^2-3x+2 textless 0}} right.; left { {{x textgreater 1} atop {(x-1)(x-2) textless 0}} right. ; left { {{x textgreater 1} atop {xin (1,2)}} right. ; ; Rightarrow ; ; xin (1,2)\\b); ; left { {{lgx textless 0} atop {x^2-3x+2 textgreater 0}} right. ; left { {{lgx textless 0} atop {(x-1)(x-2) textgreater 0}} right. ; left { {{0<x textless 1} atop {xin (-infty ,1)cup (2,+infty )}} right. ; ; Rightarrow ; ; xin (0,1)\\Otvet:; ; xin (0 ,1)cup (1,2); .$