Question

Помогите решить это ур-ние

Answer 1

$frac{x^2-x-12}{x+3} = 0 \ left { {{ frac{(x+3)(x-4)}{x+3} = 0} atop {x ne -3}} right. \ left { {{x=4} atop {x ne -3}} right. \ x = 4$

Answer 2

$frac{ x^{2}-x-12}{x+3} =0$

$x+3 neq 0 = textgreater xneq -3$

$x^{2} -x-12=0$
$left { {{x_{1}+x_{2} =1} atop {x_{1}x_{2} =-12}} right. = textgreater left { {{x_{1} =4} atop {x_{2}=-3}} right.$
$x=4$

Ответ: 4