Question

помогите с химиеййй пжжжжжжжж

Answer 1

дано
m(HCL)= 80 g
-----------------------
m(AgCL)-?

KOH+HCL-->KCL+H2O
KCL+AgNO3-->AgCL+KNO3

M(HCL) = 36.5 g/mol
n(HCL) = m/M = 80 / 36.5 = 2.19 mol
n(HCL) = n(AgCL) = 2.19 mol
M(AgCL) = 143.5 g/mol
m(AgCL) = n*M = 2.19 * 143.5 = 314.265g
ответ 314.265 г