Question

Разложите на множители
81p^2 -4(6p+1)^2

Answer 1

$81p^2 -4(6p+1)^2=(9p)^2-(2(6p+1))^2 = \ = (9p-2(6p+1))(9p+2(6p+1)) = (9p-12p-2)(9p+12p+2) = \ = (-3p-2)(21p+2) = -(3p+2)(21p+2)$

Answer 2

Мда, удалили