Question

найдите корни уравнения (x-2)^2=(x+1)^2

Answer 1

x^2-4x+4=x^2+2x+1
x^2-x^2-4x-2x=1-4
-6x=-3
x=-3/-6
x=1/2
x=0.5

Answer 2

$(x-2)^2=(x+1)^2\\(x-2)^2-(x+1)^2=0; ,qquad A^2-B^2=(A-B)(A+B)\\(x-2-(x+1))(x-2+x+1)=0\\-3cdot (2x-1)=0\\x=frac{1}{2}$