Question

Как решить линейное уравнения:
1/3х=12, -4х=1/7, 1/6y=1/3

Answer 1

1)
$frac{1}{3}x = 12$
$x = 12 / frac{1}{3}$
$x = 4$
2)
$- 4x = frac{1}{7}$
$x = frac{1}{7} / (-4)$
$x = - frac{1}{28}$
3)
$frac{1}{6}y = frac{1}{3}$
$y = frac{1}{3} / frac{1}{6}$
$y = 2$

Answer 2

1) 1/3 х = 12
х = 12/  1/3 = 12* 3/1
х = 36
2) - 4х = 1/7
х = 1/7  / (-4) = 1/(7 * (-4)) = - 1/28
х = - 1/28
3) 1/6у = 1/3
у = (1/3) / (1/6) = (1/3) / (6/1)
у = 2