Question

Выполните задание,срочно

Answer 1

$x= sqrt[3]{a} ;y= sqrt[3]{b} \ \ left { {{x+y=6} atop {x^3+y^3=72}} right. \ \ x^3+(6-x)^3=72 \ \ x^3+216-108x+18x^2-x^3=72 \ \ 18x^2-108x+144=0 \ \ x^2-6x+8=0 \ \ D=36-32=4 \ \ x=(6+2)/2=4;y=2 \ \ a=4^3=64;b=2^3=8 \ \ x=(6-2)/2=2;y=4 \ \ a=2^3=8;b=4^3=64 \ \ OTVET : (8;64)(64;8)$