Question

Решите уравнение
sin(x+П/3)=1/2

Answer 1

х1+π/3=π/6+2*π*N⇒x1=π/6+2*π*N-π/3=(π-2*π)/6+2*π*N=2*π*N-π/6.
x2+π/3=5*π/6+2*π*N⇒x2=5*π/6+2*π*N-π/3=(5*π-2*π)/6+2*π*N=2*π*N+π/2.
Во всех случаях N принадлежит множеству целых чисел.