Question

Решите пожалуйста (3ц.2/3+1ц.3/4):(6ц7/12-2ц.1/4)=
1)
2)
3)

Answer 1

(3 2/3 + 1 3/4) : (6 7/12 - 2 1/4) = 1 целая 1/64

1) 3 2/3 + 1 3/4 = 3 8/12 + 1 9/12 = 4 17/12 = 5 целых 5/12
2) 6 7/12 - 2 1/4 = 6 7/12 - 1 3/12 = 5 4/12 = 5 целых 1/3
3) 5 5/12 : 5 1/3 = 65/12 : 16/3 = 65/12 * 3/16 = (65*1)/(4*16) = 65/64 = 1 1/64