Question

помогите решить уравнение

Answer 1

$log_{3} ^{2} (x) - 2 log_{3}(x) = 3 \ odz : : : x > 0 \ log_{3}(x) =y \ {y}^{2} - 2y = 3 \ {y}^{2} - 2y - 3 = 0 \ d = 4 - 4 times ( - 3) = = 4 + 12 = 16 \ y1 = frac{2 + sqrt{16} }{2} = frac{2 + 4}{2} = frac{6}{2} = 3 \ y2 = frac{2 - sqrt{16} }{2} = frac{2 - 4}{2} = - frac{2}{2} = - 1 \ - - - - - \ log_{3}(x) = y1 \ log_{3}(x) =3 \ x1 = 27 \ - - - - - - \ log_{3}(x) =y2 \ log_{3}(x) = - 1 \ x2 = frac{1}{3} : : : \ odz : : : : : x > 0$