Question

Решите уравнение:1) (2х-3)^2=0 2)(5-х)^2=-(4-х)(х+4)

Answer 1

$1)4 x^{2} -12x+9=0 \ \ D=144-16*9=0 \ \ x=12/8=3/2=1.5 \ \ \ 2)25-10x+ x^{2} =-(16- x^{2} ) \ \ 25-10x+ x^{2} =-16+x^{2} \ \ -10x=-39 \ \ x=3.9$