Question

Решите уравнение:
(3x+4)во второй -(3x-1)(1+3x)=65

Answer 1

$(3x + 4)(3x + 4) - (3x - 1)(1 + 3x) = 65 \ 9 {x}^{2} + 24x + 16 - (9 {x}^{2} - 1) = 65 \ 9 {x}^{2} + 24x + 16 - 9 {x}^{2} + 1 = 65 \ 24x = 48 \ x = 2$